b^2+2b=8

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Solution for b^2+2b=8 equation:


Simplifying
b2 + 2b = 8

Reorder the terms:
2b + b2 = 8

Solving
2b + b2 = 8

Solving for variable 'b'.

Reorder the terms:
-8 + 2b + b2 = 8 + -8

Combine like terms: 8 + -8 = 0
-8 + 2b + b2 = 0

Factor a trinomial.
(-4 + -1b)(2 + -1b) = 0

Subproblem 1

Set the factor '(-4 + -1b)' equal to zero and attempt to solve: Simplifying -4 + -1b = 0 Solving -4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1b = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1b = 0 + 4 -1b = 0 + 4 Combine like terms: 0 + 4 = 4 -1b = 4 Divide each side by '-1'. b = -4 Simplifying b = -4

Subproblem 2

Set the factor '(2 + -1b)' equal to zero and attempt to solve: Simplifying 2 + -1b = 0 Solving 2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1b = 0 + -2 -1b = 0 + -2 Combine like terms: 0 + -2 = -2 -1b = -2 Divide each side by '-1'. b = 2 Simplifying b = 2

Solution

b = {-4, 2}

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